two friends deepak and rajeev have agreed to meet at a definite spot on a particular day between 9pm and 10pm. the first person to come waits for some time and leaves.If the other one does not turn up by that time.If Deepak comes first,he waits for 45minutes and if Rajeev comes first,he waits for 15minutes.What is the probability of meeting between Deepak and rajeev if their arrival times are independent of eachother and each person arrives during the indicated period at random?
a. 3/4 b. 11/16 c. 7/8 d. 3/16

• deepak : 45/60 = 3/4
  rajeev : 15/60= 1/4
  as these are independent events
  total probability = (3/4)*(1/4)
  = 3/16
  Ps: correct me if i was wrong
• 10 years agoHelpfull: Yes(50) No(2)
• answer==> P(E)= 3/4*1/4=3/16
  as chances of deepak = 45/60=3/4
  chances of rajeev = 15/60= 1/4
  hence P(E)= 3/4*1/4= 3/16
• 10 years agoHelpfull: Yes(4) No(1)
• when deepak comes he wait 45mins& if rajeev comes first he wait 15 min.so their metting time is 45 mins
  so it should be 45/60;
  3/4
• 10 years agoHelpfull: Yes(0) No(0)
• deepak rajeev
  45/60 15/60 =3/4*3/4+1/4*3/5
  =3/4 ans
• 10 years agoHelpfull: Yes(0) No(0)
• 1 hr-->60 min
  INDEPENDENT EVENT=(45/60)*(15/60)
  3/16
• 10 years agoHelpfull: Yes(0) No(0)
• this is gate 2012 question.not tcs question.
  anwer is
  (45/60)*(15/60)=(3/16)
• 9 years agoHelpfull: Yes(0) No(0)