In a stream running at 2kmph,a motar boat goes 6km upstream and back again to the starting point in 33 minutes.find the speed of the motarboat in still water.

• Ans is 22km/h
  let X is the speed of the boat in still water
  from the given data
  6000/(x-2000/60)+6000/(x+2000/60)=33-----(1)
  solve equation 1 for X you will get x=22kmph
• 9 years agoHelpfull: Yes(9) No(0)
• let speed of boat in still water is u.
  distance=6km(given)
  in upstream speed=(u-2)
  where stream speed=2
  in down stream speed=(u+2)
  so,d/(u-2)+d/(u+2)=33/60
  6/(u-2)+6/(u+2)=33/60
  solve and get u=22
  so speed of boat in still water=22kmph
• 9 years agoHelpfull: Yes(6) No(0)
• 6/(x-2)+6/(x+2)=33/60
  x=(284/11)^.5
• 9 years agoHelpfull: Yes(1) No(4)
• speed of the stream s=2kmph
  speed of the boat b=xkmph
  distance of up stream d(up)=6km
  distance of up stream d(down)=6km
  [d(up)/(b-s)]+[d(down)/(b-s)]=33/60
  by this we can get b=33/720 kmph
• 9 years agoHelpfull: Yes(0) No(3)