A number when divided successively by 4 and 5 leaves remainder 1 and 4 respectively When it is successively divided

Ans. 4. 5
1. 4.
Mum=4*4+1=17
Divide successively by 5 & 4 u will get
2 & 3
9 years agoHelpfull: Yes(4) No(5)
:

4 | x y = (5 x 1 + 4) = 9
--------
5 | y -1 x = (4 x y + 1) = (4 x 9 + 1) = 37
--------
| 1 -4

Now, 37 when divided successively by 5 and 4, we get

5 | 37
---------
4 | 7 - 2
---------
| 1 - 3

Respective remainders are 2 and 3.
9 years agoHelpfull: Yes(2) No(1)
answer is 4 and zero
9 years agoHelpfull: Yes(1) No(0)
Ans. 2 and 3

Soln.
Let no. be x

4|x
5|y - 1
|1 - 4
ie. y=5*1+4=9
x=4*y+1=37

5|37
4|7 - 2
|1 - 3
hence, rem. 2 & 3 resp.
9 years agoHelpfull: Yes(0) No(0)
formula is if a^r/r here r is prime
then remaider will be a;;;
so 2^47%47=2
9 years agoHelpfull: Yes(0) No(0)
its Euler formula a^p mod p =a ;when p is a prime number.
9 years agoHelpfull: Yes(0) No(0)
its very easy number is 9.
it gives remainder 1 when divided by 4
it gives remainder 4 when divided by 5

so answer will be 4 and 1.
9 years agoHelpfull: Yes(0) No(3)

A number when divided successively by 4 and 5 leaves remainder 1 and 4 respectively. When it is successively divided by 5 and 4, then the respective remainders will be;