There are 5 men and 11 women. In how many ways one can select a group of 6 with at-least 3 men?

• 3M3W+4M2W+5M1W
  5c3*11c3+5c4*11c2+5c5*11c1
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• (5c3*11c3)+(5c4*11c2)+(5c5*11c1)
  1936
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• 5c3*11c3+5c4*11c2+5c5*11c1=1936
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• 5men 11women
  5c3 11c3
  5c4 11c2
  5c5 11c1
  so 5c3*11c3+5c4*11c2+5c5*11c1=1936
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• total=6 men(5) women(11)
  3 3
  4 2
  5 1
  no of ways=(5c3*11c3)+(5c4*11c2)+(5c5*11c1)=1936
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• sample space S=16C6
  selecting atleast 3 men N=(5c3*11c2)+(5c4*11c1)+(5c5)
  so,the number of ways=N/S
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• sorry...
  ((11c3*5c3)+(11c2*5c4)+(11c1*5c5))/16c6
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• 5+11=16 getting 6 from 16= 16C6=8008
  3 are from women 11C3 and remaining from men 5C3 ...11c3*5c3=1650
  the probability..... 1650/8008 =75/364
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