Jack and Paul are running 1000m. Jack runs 1.5Km/hr faster than Paul but also finishes the race 1.5 sec earlier. What is the speed of Jack??

• distance(given) 1000m
  paul speed(let)= x m/s
  time(paul take)= 1000/x sec
  jack speed= x + 1.5*(5/18) m/s
  tym (jack)= 1000/(x+7.5/18) s
  tym(paul) - tym (jack) = 1.5
  solving for x we get 20.20
  speed of jack is 20.20+ 7.5/18=20.61
  
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• (1000/(x+1.5))-(1000/x)=1.5*5/18
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• let the spped of jack be j and speed of paul p
  then j-p=1.5
  1000/j-1000/-1.5+j=-1.5
  sloveing above eq we het 1000m/s
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• Can you explain me clearly plz..
  
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• ans is approxmately 20 meter/sec
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