if the sum of n terms of two arithmetic progressions are in ratio (7n+1):(4n+25) then the ratio of their 5th term is

• ans:- 4:5
  
  Solution:-
  
  the ratio of 5th term
  
  (7*5+1):(4*5+25)
  4 : 5
• 10 years agoHelpfull: Yes(0) No(2)
• S1n= (7n+1)k and S2n=(4n+25)k
  5th term of 1st A.P. = S15- S14 and 2nd A.P. = S25-S24
  Hence Ratio= 7*(5-4)/4*(5-4)= 7/4
  
• 10 years agoHelpfull: Yes(0) No(0)