George does 3 5th of a piece of work in 9 days He then calls in Paul and they finish

Let the time taken by George be x days

Then the time taken by them to do a work jointly= 15*x/(15+x)

Now 2/5 of the work is left which is completed in 4 days

So [15*x/(x+15)]*(2/5)=4

=>15*x/(x+15)=10

=>15x=10x+150

=>5x=150

=>x=30
So 30 days would be required by Paul to do the work himself.
9 years agoHelpfull: Yes(4) No(0)
george does 3/5th work in 9 days,so total days needed by him =15 days
remaining work=2/5
so equation is 1/15+1/x=1/4(2/5)
where x=time taken by pauli.e.30 days
9 years agoHelpfull: Yes(3) No(0)
3/5 in 9 days
2/5 in 6 days for george
but 2/5 in 4 days
paul can do it in 2/5 in 12 days(1/6+1/p=1/4 then 12 days)
so 3/5 work is 18 days
total 12+18=30
9 years agoHelpfull: Yes(3) No(0)
ans: 60/11
george does 3/5 of a piece of work in 9 days.

he finish his work in 9*5/3=15 days.

let , paul take x days to finish his work.

so they finish together in (15*x)/15+x = 4

=> x=60/11 days
9 years agoHelpfull: Yes(2) No(9)
9 days = 3/5
1 day= 1/15
3/5 work is done, remainin work= 2/5
work done by george in next 4 days = 4/15
by paul= 2/5-4/15
=2/15 wich is work of 4 days.
1 day work= 1/30
so,total days required=30
9 years agoHelpfull: Yes(2) No(0)

George does 3/5th of a piece of work in 9 days.He then calls in Paul and they finish the work in 4 days.How long would Paul take to do the work by himself?