Average marks of a,b,c is 48. When d joins average becomes 47. E has 3 more marks than d. Average marks of b,c,d,e is 48. What is the marks of a?

• a+b+c=144
  a+b+c+d=188
  d=44
  e=47
  b+c+d+e=192
  b+c=101
  a=43 ans.
• 9 years agoHelpfull: Yes(42) No(8)
• a+b+c=48*3=144
  a+b+c+d=47*4=188
  b+c+d+e=48*4=192
  d=188-144=44
  e=3+44=47
  b+c+d=192-47=145
  a=188-145=43
• 9 years agoHelpfull: Yes(11) No(1)
• avg of a,b,c is 48
  sum of a,b,c is (48)*3=144 (avg=sum/count hence sum=avg*count)
  avg of a,b,c,d is 47
  sum of a,b,c,d is 47*4=188
  d marks=(sum of a,b,c,d)-(sum of a,b,c)=188-144=44
  e has 3 marks more than d
  e marks are 47
  d+e marks are=91
  avg of b,c,d,e is 48
  sum of b,c,d,e is 48*4=192
  b+c+d+e=192
  d+e=91
  hence b+c=101
  a+b+c=144
  a+101=144
  a=144-101=43
  marks of a is 43
• 9 years agoHelpfull: Yes(7) No(0)
• let average marks of a,b, c be x.
  then x/3=48
  hence,x=144
  or, a+b+c =144 ............ (1)
  now,
  d joins.
  now average becomes 47,
  so, (x+d)/4=47 .............(2)
  144+d=188
  d=44
  given, e=d+3
  e=47
  now again, (b+c+d+e)/4=48 ........... (3)
  b+c+44+47=192
  b+c=101
  and from eqn 1,
  a+b+c=144
  hence , a= 144-101
  a=43.
• 9 years agoHelpfull: Yes(2) No(1)
• a+b+c=144
  a+b+c+d=188
  By solving
  d=44
  e=47
  b+c+d+e=192
  Then
  b+c=101
  a+b+c=144
  Then
  a=43
• 9 years agoHelpfull: Yes(1) No(0)
• a+b+c=144
  a+b+c+d=188
  d=44
  e=47
  b+c+d+e=192
  b+c=101
  a=43 ans.
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• 8 years agoHelpfull: Yes(1) No(0)
• A scored 43.
• 9 years agoHelpfull: Yes(0) No(0)
• sum of a+b+c=144 and avg=48
  when d join average become 47.so d must be 44
  and e=d+3=47
  B+C+44+47=48*4
  b+c=101
  so,
  a+101=44
  hence a=43
• 9 years agoHelpfull: Yes(0) No(0)
• (a+b+c)/3=48 =>a+b+c=144
  (a+b+c+d)/4=47 =>a+b+c+d=188 =>d=188-144, so d=44, e=47
  (b+c+44+47)/4=48 => b+c=101
  from 1st line, a=144-101
  so a=43(Ans)
• 9 years agoHelpfull: Yes(0) No(0)
• a+b+c=48*3=144
  a+b+c+d=47*4=188
  e=d+3
  b+c+d+e=48*4=192
  144+d=188
  d=44
  e=47
  a=43
• 5 years agoHelpfull: Yes(0) No(0)
• my ans is 43
• 4 years agoHelpfull: Yes(0) No(0)