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When the sum of four consecutive odd numbers is divided by 10, the number obtained is a perfect square. Which one of the following is one of the four consecutive odd numbers?
Read Solution (Total 9)
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- Ans:- four consecutive odd numbers :- 7, 9, 11, 13
let four consecutive odd number be 2x-3, 2x-1, 2x+1, 2x+3
so,
= (2x-3+2x-1+2x+1,2x+3)/10
= 8x/10
= 4x/5 {for perfect square....}
x = 5
four consecutive odd numbers :- 7, 9, 11, 13
- 10 years agoHelpfull: Yes(19) No(0)
- 37+39+41+43=160
160/10=16 and now 16 is square of 4... - 10 years agoHelpfull: Yes(4) No(0)
- 87+89+91+93=360
360/10= 36 - 10 years agoHelpfull: Yes(1) No(0)
- 7+9+11+13=40/10=4=2^2 perfect square .
- 10 years agoHelpfull: Yes(1) No(0)
- 37+39+41+43= 160/10=16= 4^2 but coorect question is not the four consecutive odd number
- 10 years agoHelpfull: Yes(1) No(0)
- 7+9+11+13=40
Now, 40/10= 4, which is a perfect square. - 10 years agoHelpfull: Yes(0) No(0)
- here answer is depend at the option ... it may 16 or 64 or etc
- 10 years agoHelpfull: Yes(0) No(0)
- 97, 99, 101, 103
- 10 years agoHelpfull: Yes(0) No(0)
- 7, 9, 11, 13
let four consecutive odd number be 2x-3, 2x-1, 2x+1, 2x+3
so,
= (2x-3+2x-1+2x+1,2x+3)/10
= 8x/10
= 4x/5 {for perfect square....}
x = 5
four consecutive odd numbers :- 7, 9, 11, 13
- 10 years agoHelpfull: Yes(0) No(0)
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