New age consultants have three consultants Gyani, Medha, and Buddhi. The sum of the number of projects handled by Gyani and Buddhi individually is equal to the number of projects in which Medha involved. All three consultants are involved together in 6 projects. Gyani works with Medha in 14 projects. Buddhi has 2 projects with with Medha but without Gyani and 3 projects with Gyani but without Medha. The total number of projects for New age consultants is one less than twice the number of projects in which more than one consultant is involved.
What is the number of projects in which Medha alone is involved?

• ans is 1
  gyani works with medha but with out buddhi=14-6=8.
  buddhi with medha but without gyani=2
  buddhi with gyani but without medha=3
  all three involved projects=6
  so number projects in which more than one consultant is involved=8+2+3+6=19
  total no.projects for consultants is 2*19-1=37
  among 37 projects in 19 projects more than one consultant is involved
  so no. of projects done by onle one consultant=37-19=18
  so b+g=16+x
  b+g=17
  x=1
• 10 years agoHelpfull: Yes(19) No(1)
• NARASAPU HARI PRASAD why r u taking b+g=16+x??? plz xplain ASAP
• 10 years agoHelpfull: Yes(8) No(0)
• 22 projects
  Using Venn diagrams
• 10 years agoHelpfull: Yes(3) No(1)
• Step 1: It was given that all the three consultants are involved in 6 projects together. So put 6 where all the three circles intersect
  Step 2: Buddhi has 2 projects with Medha but without Gyani. i.e., Medha and Buddhi alone worked in 2 projects.
  Step 3: Also given, Buddi worked on 3 projects with Gyani but without Medha. i.e., Buddi adn Gyani alone worked on 3 projects.
  Step 4: Gyani worked with Medha in 14 projects. These two worked together along with Buddhi in 6 projects. So Gyani and Medha alone worked on 14 - 6 = 8 Projects.
  
  
  Lets us assume, Gyani, Buddhi and Medha alone worked on a, b, c projects.
  
  It was given that The sum of the number of projects handled by Gyani and Buddhi individually is equal to the number of projects in which Medha involved.
  ⇒⇒a + b = 8 + 6 + 2 + c
  ⇒⇒ a + b = 16 + c ------------------ (1)
  
  Also given The total number of projects for New age consultants is one less than twice the number of projects in which more than one consultant is involved.
  
  The projects in which more than 1 consultant involved = 6 + 3 + 2 + 8 = 19
  Total projects = a + b + c + 8 + 3 + 2 + 6 = a + b + c + 19
  ⇒⇒ 2××19 - 1 = a + b + c + 19
  ⇒⇒a + b + c = 18
  ⇒⇒ a + b = 18 - c
  
  Substituting this value in equation (1) we get
  18 - c = 16 + c ⇒⇒ c = 1
  
  So from equation (1) we get a + b = 17.
• 8 years agoHelpfull: Yes(1) No(0)
• ans:9
  no. of projects done by all three individually is 18
  -->g+m+b=18--(eq1)
  in first start statement g+b=m
  -->m=-g-m in eq1
  gives m=9
• 10 years agoHelpfull: Yes(0) No(0)
• y b+g=16+x.. can anyone please explain..?
• 10 years agoHelpfull: Yes(0) No(0)