A chef cuts a watermelon along its horizontal diameter once and then along its vertical diameter twice at right angle to each other. A slice is removed (other pieces remains intact). What will be the total surface area of the remaining portion?

• surface area of sphare is (4*pi*r^2)
  if 1/4th parth is removed (4*pi*r^2)-(pi*r^2)= 3*pi*r^2
  and the cut surface is (1/2*pi*4^2)*2
  so total surface area is 4*pi*r^2 ans.
• 9 years agoHelpfull: Yes(7) No(6)
• surface area of a sphere is =4*pi*r^2
  when it is cut horizontally =2
  when it is cut once vertically=4
  when again cut perpendicular to initial vertical cut= 8 pieces(4 from upper hemisphere+4 from lower hemisphere)
  now one slice is removed.so remaining outer surface area=7/8(4*pi*r^2)
  now in the depth of removed slice portion,3 quadrants of radius r is produced due removed slice. of area 1/4*pi*r^2 each
  so total surface area=( 7/2*pi*r^2+3*1/4*pi*r^2)= 17/4*pi*r^2
• 9 years agoHelpfull: Yes(7) No(1)
• It is 7/6pi r ^3
  When 1/8th portion is removed from the watermelon
• 9 years agoHelpfull: Yes(3) No(1)
• ans. (17/4)*pi*r^2
• 9 years agoHelpfull: Yes(2) No(0)
• Curved surface area is 1/8 of the total surface area of the melon
  i.e 1/8*pi*r^2
  And flat surface is equal to 1/2*r^2*pi/2 but dere r 3 symmetrical ones
  i.e 3/4*pi*r^2
  Therefor total surface area equals to pi*r^2*5/4
• 9 years agoHelpfull: Yes(0) No(1)
• surface area of a sphere is 4*pi*r^2.
  when it is cut horizontally =two pieces
  when it is cut once vertically=4pieces
  when again cut perpendicular to initial vertical cut= 8 pieces(4 from upper hemisphere+4 from lower hemisphere).
  now one slice is removed.so remaining outer surface area=1/2*pi*r^2.
  now in the depth of removed slice portion,3 quadrants of radius r is produced due removed slice. of area 1/4*pi*r^2 each
  so total surface area=( 1/2*pi*r^2+3*1/4*pi*r^2)= 5/4*pi*r^2
  
• 9 years agoHelpfull: Yes(0) No(1)
• its 7/8th part of 4*pi*r^2 and 3/4th part of pi*r^2
• 9 years agoHelpfull: Yes(0) No(1)