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In a certain code VOLITION is written as UMIEUKRR, MARTINET is written as LYOPJPMX. How is DESTROYS written in this code?
Read Solution (Total 12)
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- order is -1,-2,-3,-4,+1,+2,+3,+4
Ans:- CCPPSQBW - 10 years agoHelpfull: Yes(20) No(1)
- as per the sequence the
ans is D-1 = C
E-2 = C
S-3=P
T-4=P
R+1=S
O+2=Q
Y+3=B
S+4=W
ans is CCPPSQBW
- 10 years agoHelpfull: Yes(7) No(0)
- alphabetical order is -1,-2,-3,-4,+1,+2,+3,+4
so answer is CCPPSQBW - 10 years agoHelpfull: Yes(1) No(0)
- CCPPSQBW. see the pattern first four letters are decreasing by 1,2,3,4 letter resp. and last four are increasing by 1,2,3,4 letters respectively
- 10 years agoHelpfull: Yes(1) No(0)
- given in question that DESTROYS
TAKE first 4 latter that is DEST
D-1=C
E-2=C
S-3=P
T-4=P
now take last 4 latters
R+1=S
O+2=Q
Y+3=B
S+4=W - 10 years agoHelpfull: Yes(1) No(0)
- It is ccppsqbu
- 10 years agoHelpfull: Yes(0) No(0)
- CCPPSQBW
-1 -2 -3 -4 +1 +2 +3 +4 The order follows - 10 years agoHelpfull: Yes(0) No(0)
- it is CCPPSRBW
- 10 years agoHelpfull: Yes(0) No(0)
- CCPPSQBW...depends on position and divided into first and second half
- 10 years agoHelpfull: Yes(0) No(0)
- CCPPSQBW
order is -1-2-3-4 +1+2+3+4 - 10 years agoHelpfull: Yes(0) No(0)
- how had u related the relation between E from MARTINET with M from LYOPJPMX ????simlilary for T wit x
- 10 years agoHelpfull: Yes(0) No(0)
- alphabetical order is -1,-2,-3,-4,+1,+2,+3,+4
so answer is CCPPSQBW
as per the sequence the
ans is D-1 = C
E-2 = C
S-3=P
T-4=P
R+1=S
O+2=Q
Y+3=B
S+4=W
ans is CCPPSQBW
CCPPSQBW. see the pattern first four letters are decreasing by 1,2,3,4 letter resp. and last four are increasing by 1,2,3,4 letters respectively - 10 years agoHelpfull: Yes(0) No(0)
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