What is the probability of getting sum 10 with the help of three dice?

• the following has 6 permutations.
  (1, 3, 6),(1, 4, 5),(2, 3, 5)
  Each of the following has 3 permutations.
  (2, 2, 6),(2, 4, 4),(3, 3, 4)
  
  the total possibility = 6*3 + 3*3 = 27
  total no. of outcomes = 6*6*6 = 216
  probability = 27/216 = 1/8 = 0.125
• 10 years agoHelpfull: Yes(24) No(1)
• (1,3,6) 3!=6 (2,2,6) =3!/2=3
  (1,4,5) 3!=6 (2,4,4)=3
  (2,3,5) 3!=6 (3,3,4)=3
  
  prob. of getting sum 10 =(6+6+6+3+3+3)/216 =1/8 Ans
  
  
  
  
• 10 years agoHelpfull: Yes(7) No(1)
• answer is 27/216
  
  
• 10 years agoHelpfull: Yes(2) No(0)
• 21/216
  for 3 dice 6^3=216
  and for sum 10 is 21
  so 21/216
• 10 years agoHelpfull: Yes(1) No(2)
• total possibilities are=
  136=3!
  235=3!
  343=3!/2
  442=3!/2
  541=3!
  622=3!/2
  total = 27
  total sample we have 6*6*6
  p(E)=27/(6*6*6)=1/8
  so 1/8 is the answer
• 10 years agoHelpfull: Yes(1) No(0)
• 1,6,3 in 6 ways 1,4,5 in 6ways 2,4,4 in 3 ways 2,5,3 in 6 ways 3,4,3 in 3 ways ans:27/216
  
• 10 years agoHelpfull: Yes(0) No(1)
• Is the answer 27
• 10 years agoHelpfull: Yes(0) No(2)
• answer is 1/8 i.e., 27/216
• 10 years agoHelpfull: Yes(0) No(0)
• there are 6 different combinations where 3 die can add up to 10:
  
  Each of the following has 6 permutations.
  
  1, 3, 6
  1, 4, 5
  2, 3, 5
  
  Each of the following has 3 permutations.
  
  2, 2, 6
  2, 4, 4
  3, 3, 4
  
  We now have 6⋅3+3⋅3=27
  
  The total number of combinations of three die rolls comes out to 63. Therefore, the probability you're looking for is:
  
  27/216=18=0.125
• 9 years agoHelpfull: Yes(0) No(0)