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The price of groudnuts increased by x%per week over 2 successive weeks. If at the begining, 2 Kgs were available for Rs 80 and after 2 weeks they were available for Rs 105.80, what is the value of x?
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- by using compound interest :-
P=80, A=105.80 n=2 r=??
105.80=80*((1+r/100)^2)
r=15% Ans
- 10 years agoHelpfull: Yes(28) No(0)
- 1st week
1 kg = 40
40 x% = 40+ (40*x)/100 = 40 {1+(x/100)}
2nd week
again 40%
=> 40 { 1+ (x/100)}^2 = 105.8/2 = 52.9
=> 1+(x/100) = 1.15
=> x = 15
so the increasing rate per week is 15% - 10 years agoHelpfull: Yes(22) No(1)
- ans is 15%
let y is the percentage at which the price increased weekly
(80*(y)/100)*y/100=105.80
by solving you get y=115
so increased percentage is 115-100=15 - 10 years agoHelpfull: Yes(5) No(0)
- x=16.12%
per week increased amount per kg=((105.80/2)-(80/2))/2=6.45
x=(6.45/40)*100
=16.12%
- 10 years agoHelpfull: Yes(4) No(3)
- 15% is the solution
solving 40*x/100 + 40
and next week 40(x/100 + 1)^2=105.8/2
on solving 15% - 10 years agoHelpfull: Yes(2) No(0)
- ans is 15
- 10 years agoHelpfull: Yes(1) No(0)
- Answer is 15......
Agree with Bhaskar - 10 years agoHelpfull: Yes(1) No(1)
- 15% let go by answer and solve it
- 10 years agoHelpfull: Yes(1) No(0)
- y=40
y+2x=52.9
thus, x=6.45
- 10 years agoHelpfull: Yes(1) No(4)
- ans= 15%
80*(1+x/100)^2 = 105.80
x= 15% - 10 years agoHelpfull: Yes(1) No(0)
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