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what is the remainder when the number 1,2,3,.........44,63 divided by 45?
Read Solution (Total 10)
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- 1,2,3,....44
sum of 44 no.=n*n-1/2=44*45/2=990
990+63=1053
1053/45...gives remainder=18.
- 10 years agoHelpfull: Yes(15) No(2)
- I think the remainder is 18 because the sum of first 44 terms is 990 so 990+63=1053 and 1053/45 gives remainder 18.
please tell the correct answer - 10 years agoHelpfull: Yes(3) No(1)
- 45=9*5
Let N=123456......44
Remainder when N is divided by 5 is 4
therefore N=5K+4 ....(1)
remainder when N is divided by 9=>990/9=remainder is 0
therefore N=9L ....(2)
From 1 and 2 we get
9L=5K+4
For K=1 this condition gets setisfied.
Least possible number satisfies the condition is 9.
Hence general format of N=w(L.C.M of 9 & 5)+least nmber satifies the condition.
N=w.45+9
So when N gets devided by 45 we gets 9 as remainder.
Ans. is 9
Please correct me if I am wrong...
- 10 years agoHelpfull: Yes(2) No(6)
- Question May be in complete
- 10 years agoHelpfull: Yes(1) No(0)
- 45=9*5.1,2,3,....44,1053 =9 so divisble by 9 but not by 5 so last 2 digit 53 %5=3
- 10 years agoHelpfull: Yes(0) No(2)
- Ans: 36
when 45 divides all numbers we get 1161 as remainder(n(n+1)/2)
- 10 years agoHelpfull: Yes(0) No(2)
- 3..
n pls let me know d correct ans - 10 years agoHelpfull: Yes(0) No(2)
- can u explain it clearly gaurav pls
- 10 years agoHelpfull: Yes(0) No(2)
- i m still unclear with the question.
- 10 years agoHelpfull: Yes(0) No(0)
- 44*45/2*45 ----> no remainder
63/45 -----> 18 remainder ! - 10 years agoHelpfull: Yes(0) No(0)
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