In a first 10 over of cricket game, the run rate was only 3.2.what should be run rate in the remaining 40 over’s to reach the target of 282 runs

• in the first 10 over,runs made=3.2*10=32
  now to reach a target to 282,where 32 runs are already made
  i.e. 282-32=250 runs are more req.
  so,run rate=250/40
  =6.25
• 10 years agoHelpfull: Yes(27) No(1)
• i think 6.25
  
• 10 years agoHelpfull: Yes(5) No(0)
• In first 10 overs they scored (10*3.2)=32, now we have to score 282-32=250 runs,
  so . .
  . in 40 overs they have to score runs =250
  .
  . . in 1 over they have to score runs = (250*1)/40= 6.25
• 10 years agoHelpfull: Yes(3) No(0)
• ans:6.25
  3.2*10+40*x=282
  x=6.25
  
• 10 years agoHelpfull: Yes(2) No(0)
• This is a question on averages .
  to reach the target of 282 runs in 10+40 overs he must on an average score 282/50= 5.6 in each over.
  so using weighted averages
  5.6=(10 X 3.2 + 40 x r)/(10+40)
  solving it for the value of r , we get r=6.2
• 10 years agoHelpfull: Yes(1) No(0)
• at the end of 10 over total run = 32
  now required run in 30 over= 282-30 = 250
  so required run rate will be = 250/30 =8.33
  
  ans:8.33
• 10 years agoHelpfull: Yes(1) No(2)
• let avg=x
  8*30+x/9+20=x
  solve x=292.50
• 10 years agoHelpfull: Yes(0) No(1)
• sorry dis sol for previous question.
  
• 10 years agoHelpfull: Yes(0) No(0)
• 3.2 for first 10 ovrs means remaining 282-(3.2*10)=250 in 40 ovs if we consider the match exactly ends at the last ball then the runrate needed will be(250/40)=6.25/over
• 10 years agoHelpfull: Yes(0) No(0)
• 10 overs ki 32 runs
  
  required 282-32=250 runs
  i.e., required run rate=250/40=6.25
• 10 years agoHelpfull: Yes(0) No(1)
• ans=
  1st 10 over run=10*3.2=32
  282-32=250
  250 run in 40 over
  avg=250/40
  =6.25
• 10 years agoHelpfull: Yes(0) No(0)
• runs in first 10 over 3.5*10= 35
  remainig run 280-30=250 then run rate = 280/40=6.25
• 10 years agoHelpfull: Yes(0) No(0)
• per over 6.25 runs
• 10 years agoHelpfull: Yes(0) No(0)
• 282-(3.2*10)=250
  250/40=6.25
• 10 years agoHelpfull: Yes(0) No(0)
• runs in first 10 over... 32 than
  282-32=250 runs are required in 49 over than run rate= 250/40
  .......6.25
• 10 years agoHelpfull: Yes(0) No(0)
• in 1st 10 overs, runs made,10*3.2=32
  required run at the end of 50 overs is 282, so in next 40 overs 282-32=250 runs required
  so 250/40= 6.25
• 10 years agoHelpfull: Yes(0) No(0)
• ans is 6.25
• 10 years agoHelpfull: Yes(0) No(0)
• 6.25 is the ans
  
• 10 years agoHelpfull: Yes(0) No(0)
• 6.25
  in first 10 over runs =3.2*10=32
  now 282-32=250
  we have 250 run in 40 over so it is 250/40=6.25
  
• 10 years agoHelpfull: Yes(0) No(0)
• Required run rate = 282 - (3.2 x 10) = 250 = 6.25
  40 40
  
• 9 years agoHelpfull: Yes(0) No(0)
• First 10 over @3.2 = 32
  Total Score = 282
  32 already scored in 10 overs.
  So, (282-32)/40 = 250/4 = 6.25
  run rate should be 6.25
• 9 years agoHelpfull: Yes(0) No(0)
• Given, first 10 overs RR=3.2
  so,runs=3.2*10=32
  remaining runs need=282-32=250
  overs remaining=40
  so,Required RR=250%40=6.25
  so,6.25 is the answer
• 6 years agoHelpfull: Yes(0) No(0)