Elitmus
Exam
Logical Reasoning
Cryptography
GAV
YTA
XBTX
ABUS
BTPT
GXGXPX
Read Solution (Total 10)
-
- GRE
MRA
............
XBRX
ABKS
BRPR
........
GXGXPX............HINT A=4
G=6,A=4,E=3,M=9,R=7 - 10 years agoHelpfull: Yes(3) No(3)
- HINT: A=4
643
974
2572
4501
5787
626282 - 10 years agoHelpfull: Yes(1) No(0)
- in question..is value of A is given??
- 10 years agoHelpfull: Yes(1) No(0)
- @vikash.......yes A value is given
- 10 years agoHelpfull: Yes(1) No(0)
- 643
974
---------
2572
4501
5787
---------
626282 - 10 years agoHelpfull: Yes(1) No(0)
- ans 643
974
----
2572
4501
5787
--------
626282 - 10 years agoHelpfull: Yes(0) No(0)
- 643
974
----------------------
2572
4501-
5787--
------------------------
626282
------------------------ - 10 years agoHelpfull: Yes(0) No(1)
- yrrrr.... how to allocate numbers to albhabats..... please help me yr.... make me understand.......
- 10 years agoHelpfull: Yes(0) No(2)
- plz explain any one dear
- 10 years agoHelpfull: Yes(0) No(0)
- the value of A is 4 and GAV*A=XBTX
So G4V * 4=XBTX
possible values of X will be 1,2 or 3(4 * G=XB) but V * 4=_X so X will be 2.
G4V * 4=2BT2 so V wi ll be 3 or 8.
if V is 3 then G43 * 4= 2B72 and G will be 6(B=5) or 5(B=1) or 7(B=9)
but we know that B + 1=G
so G=6 and B=5... Now rest of the values can be calculated easily. - 10 years agoHelpfull: Yes(0) No(1)
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