n a and n b are the two perfect square n a b are whole numbers a 11 b 56

lets assume n+a=x^2 and n+b=y^2
n=X2-a and n=Y2-b
equate then
y2-x2=56-11=45
(y+x)(y-x)=45
so factors of 45
45*1 and 15*3 and 9*5 =45
y+x=45 y-x=1 then y=23 x=22 then n=529-56=473 and 484-11=473
y+x=15 and y-x=3 then y=9 and x=6 then n=81-56=25 and 36-11= 25
y+x=9 and y-x=5 then y=7 and x=2 the 49-56 not possible and 4-11 not possible so
ans is 473 and 25 only 2
7 years agoHelpfull: Yes(10) No(0)
n=25
only 1
10 years agoHelpfull: Yes(9) No(9)
ans is 2
n=25
n=273
10 years agoHelpfull: Yes(8) No(12)
ans is 2 only two values n=25 and n=473
10 years agoHelpfull: Yes(5) No(2)
ans is 2
n=-7
n=25
10 years agoHelpfull: Yes(1) No(20)
unit digit only depend upon unit digit that is 1 in 101 so 1 to power anything will be 1
10 years agoHelpfull: Yes(0) No(2)
Sry i m anable to answer
10 years agoHelpfull: Yes(0) No(0)
a perfect square is the product of two equal integers
e.g.
9 is a perfect square because it can be expressed as 3 * 3 (the product of two equal integers)

ans is i)none
10 years agoHelpfull: Yes(0) No(1)
In this question their is no limitation of n like,the the value of n should be less then 200,300 etc.

initially if we will put n=25,473 it satisfied but surely so many other numbers are their which might be satisfy the condition ,since limitation not given .
According to option 1) non of these will be ok.
9 years agoHelpfull: Yes(0) No(1)

(n+a) and (n+b) are the two perfect square , n,a,b are whole numbers.
a=11, b=56 so what are the possible values of n...???

i) None ii) only 1 iii) 2 iv) 4