Elitmus
Exam
Numerical Ability
Log and Antilog
f(x)=Log base a (x)+Log base b (x) and 1
Read Solution (Total 4)
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- @Gautam Raj will u plz elaborate.....
put a=2 and b=3 and
f(2)=log2base2 +log2base3
f(2)=1+log2base3
f(2)=1+.68=1.68
is that okey...
- 10 years agoHelpfull: Yes(8) No(3)
- Minimum value is nearest to 2
- 10 years agoHelpfull: Yes(3) No(2)
- 1+ log2base3
- 10 years agoHelpfull: Yes(2) No(0)
- @Kaberi Nayak
are u sure about this...and was there any option with value 2..????
i think options were 1, 1+log2base3, 0, -1...!!!!! - 10 years agoHelpfull: Yes(0) No(0)
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