Elitmus
Exam
Numerical Ability
Clocks and Calendars
(50^56^52) mod 11........ans is 5 but tell me the procedur common for other ques also
Read Solution (Total 2)
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- let N=56^52
50^N/11= 6^N/11
now we have to make cycle of 6
6^1/11=6
6^2/11=3
6^3/11=7
6^4/11=9
6^5/11=10= -1(negative remainder)
so the cycle of 50^N(or 6^N) is 10
now, N/10= 56^52/10 gives remainder=6
this 6 will be the 6th term of the cycle 50^N
so the required remainder= 6th term/11= (6^3*6^3)/11= 49/11= 5 - 10 years agoHelpfull: Yes(3) No(1)
- if p is a prime no then (a^(p-1))/p leaves rmdr=1
50^(10k+6)=(50^10k)*50^6/11
=1*6^6/11=36*36*36/11
3*3*3/11=27/11=5 ans - 10 years agoHelpfull: Yes(0) No(3)
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