(50^56^52) mod 11........ans is 5 but tell me the procedur common for other ques also

• let N=56^52
  
  50^N/11= 6^N/11
  now we have to make cycle of 6
  6^1/11=6
  6^2/11=3
  6^3/11=7
  6^4/11=9
  6^5/11=10= -1(negative remainder)
  
  so the cycle of 50^N(or 6^N) is 10
  
  now, N/10= 56^52/10 gives remainder=6
  
  this 6 will be the 6th term of the cycle 50^N
  
  so the required remainder= 6th term/11= (6^3*6^3)/11= 49/11= 5
• 9 years agoHelpfull: Yes(3) No(1)
• if p is a prime no then (a^(p-1))/p leaves rmdr=1
  50^(10k+6)=(50^10k)*50^6/11
  =1*6^6/11=36*36*36/11
  3*3*3/11=27/11=5 ans
• 9 years agoHelpfull: Yes(0) No(3)