In this question A^B means A raised to the power B. If f(x)=a*x^4-b*x^2+x+5. f(-3)=2. Then f(3)=?

• 8
  81a-9b-3+5=2
  i.e b=9a
  f(3)=81a-9b+3+5=8
• 10 years agoHelpfull: Yes(15) No(0)
• Given that f(x)=a*x^4-b*x^2+x+5
  and f(-3)=2
  so => a*(-3)^4-b*(-3)^2+(-3)+5=2
  => 81a-9b+2=2
  => 81a-9b=0 -------equation(1)
  now f(3)=a*(3)^4-b*(3)^2+3+5
  =81a-9b+8
  and from equation (1) 81a-9b=0
  so f(3)=0+8=8
• 10 years agoHelpfull: Yes(6) No(1)
• Simply 8..A bit of manipulation needed!
• 10 years agoHelpfull: Yes(1) No(0)
• f(-3)=81a-9b+(-3)+5
  or, 2=81a-9b+2
  or, b=9a
  
  f(3)= 81a-9b+3+8=81a-9*9a+8=8
  Hence the answer is 8
• 10 years agoHelpfull: Yes(1) No(1)
• having f(-3)=2,solving this,we get a relation 9*a=b
  f(3)=81*a-9*b+8,substituting the value of b,
  f(3)=8
• 10 years agoHelpfull: Yes(0) No(0)
• f(-3)= 81a-9b-3+5= 2 i.e 81a-9b=0
  f(3)= 81a-9b+8 so f(3)=8
• 10 years agoHelpfull: Yes(0) No(0)
• f(-3)=81a-9b+2
  so we get 81a-9b=0
  f(3)=81a-9b+8
  so we getf(3)=8
• 10 years agoHelpfull: Yes(0) No(0)
• answer is 8..
  
• 10 years agoHelpfull: Yes(0) No(0)
• 
  81a-9b-3+5=2
  i.e b=9a
  f(3)=81a-9b+3+5=8
  
  ans- 8
• 10 years agoHelpfull: Yes(0) No(0)
• There is no change whether it is f(-3) or f(3) up to equation a*x^4-b*x^2
  now for x+5 if you place -3 you will get 2 and if you place 3 you will get 8.
• 6 years agoHelpfull: Yes(0) No(0)
• In the given equation substitute a = b = 0 then
  f(-3) = -3 + 5 =2
  similarly f(3) = 3 + 5 =8
• 6 years agoHelpfull: Yes(0) No(0)