17*8 m rectangular grand is surrounded by 1.5 m width path.Depth of the path is 12 cm. Gravel is filled and find the quantity of gravel required in cubic meters.?

• area of the rectangular ground=(17*8)m^2=136 m^2
  taking into account the path:
  total area=[(17+(2*1.5))*(8+(2*1.5))]=220 m^2
  area of the path=220-136=84m^2
  gravel required=[84*(12/100)]=10.08m
• 9 years agoHelpfull: Yes(34) No(1)
• Depth of path=12cm=0.12m
  volume of gravel= 2(0.12*11*1.5)+2(0.12*17*1.5)=10.08 cubic meters
• 9 years agoHelpfull: Yes(4) No(0)
• 10.080 must be d ri8 ans ...
  the resulted cude are 2 of (17*1.5*.12) and 2 of (11*1.5*.12*)
  V= 2{(17*1.5*.12)+(11*1.5*.12)}=10.08 cu meters
• 9 years agoHelpfull: Yes(3) No(0)
• 1008 cubic meters.
  two length are of 17m and two are of (8+1.5+1.5)m
  volume of Gravel required= (17*1.5*12 + 17*1.5*12 + 11*1.5*12 + 11*1.5*12)=1008
• 9 years agoHelpfull: Yes(1) No(1)
• area of path = area of outer rectangle - area of inner rect
  outer rectangle len= 17+1.5+1.5, breadth= 8+1.5+1.5
  area of outer rec= 11*22 = 220
  area of inner rec= 17 * 8 =136
  area of path = 220-136 = 84
  vol of gravel = 84* 0.12=10.08
  
• 8 years agoHelpfull: Yes(1) No(0)
• answer is 9 cubic mt
  
• 9 years agoHelpfull: Yes(0) No(5)
• area of path= area of grand with path-area of grand only
  =18.5*9.5-17*8
  =175.75-138
  =39.75 m^2
  gravel required =39.75*0.12=4.77 m^3 .
  
  
• 9 years agoHelpfull: Yes(0) No(1)