1024*128+256*2+10 when base is 4 how many 2 will occur
option a)2 b)4 c)6 d)8

• 1024=1*(4^3)+0*(4^2)+2*(4)+4*(4^0)=76;
  similarly,128=1*16+2*4+8*1=32;
  256=2*16+5*4+6*1=58;
  2=2*1=2;
  10= 1*4+0*1=4;
  result= (76*32+58*2+4)=(2432+116+4)=2552
  number of 2 in 2552 is 2 then
  a) 2 is answer
• 10 years agoHelpfull: Yes(13) No(10)
• first multiply all the no. the use the basic principle of base conversion means divde the whole no. to the 4 and taking remainder..................
• 10 years agoHelpfull: Yes(4) No(3)
• b option.. 4 ans
  
• 10 years agoHelpfull: Yes(3) No(2)
• ans is b beause
• 10 years agoHelpfull: Yes(0) No(3)
• ans. is (d)8
• 10 years agoHelpfull: Yes(0) No(1)
• Answer is 4 and is correct .. 100% sure
• 9 years agoHelpfull: Yes(0) No(0)
• those who supporting option d..please clarify with the valid statement..cos am also intution with option (d) and (b) as well
• 9 years agoHelpfull: Yes(0) No(0)
• answer is two just by basic conversion law - solve it to decimal and than convert it to base 4
• 9 years agoHelpfull: Yes(0) No(0)
• 1028=4^5
  128=2x4^3
  1028*128=2*4^8
  256*2=2*4^4
  10=2*4^1+2*4^0
  now combine all this
  2*4^8+2*4^4+2*4^1+2*4^0
  so ans is a) 2
• 8 years agoHelpfull: Yes(0) No(0)