what is the max number of cone that can be cut from the cuboid of dimension 24*16*9.If the base of the cone is on one of the face of cuboid.

• ans is 8
  
  First we will find the min volumeof cone that can be made from given cuboid,in this way we can get the maximum number of cones that can be cut(cone of smallest volume).
  
  for this
  r=max(24,16)/2 r=12 ,h=9 volume=432pi
  r=max(9,16)/2 r=8,h=24 volume=512pi
  r=max(24,9)/2 r=12,h=19 volume=768pi
  
  
  take the minimum of volume i.e 432pi
  
  
  Volume of cuboid=l*b*h=3456
  max number of cones required are = volume of cuboid/volume of cone of minimum volume
• 9 years agoHelpfull: Yes(4) No(5)
• r=8 and h=9
  phi r^2h we get the ans a
• 9 years agoHelpfull: Yes(2) No(2)
• are yaar explain to karo
  
• 9 years agoHelpfull: Yes(1) No(0)
• Only restriction given is that base of the cone should be on one of the face of cuboid. Since there are no other restrictions, any value of the base radius is possible such as r=1, 2, 0.2, 0.01 etc because all such bases can be on one of the face of cuboid. Theoretically, infinite number of cones can be cut.
• 6 years agoHelpfull: Yes(1) No(1)
• r =8 and height == 24
• 9 years agoHelpfull: Yes(0) No(2)
• 1024*128+256*2+10===
  1024=4^5;
  128=4^3 * 2;
  256==4^4 ;
  
  then
  4^5 * 4^3 *2 +4^4 * 2 + 4 * 2 + 2 then
  4^8 * 2 + 4^4 * 2 + 4*2 + 4^0 * 2 then
  20002022
  
  then right ans is 4
  
  
  
• 9 years agoHelpfull: Yes(0) No(9)
• please explain Vikash
• 9 years agoHelpfull: Yes(0) No(0)
• explain please
• 9 years agoHelpfull: Yes(0) No(0)