Series Problem like 4 12 x 44 46 132 134. Find x?

• 44+2=46
  132+2=134
  lly 12+2=14 so x=14;
• 14 years agoHelpfull: Yes(19) No(41)
• divide odd places by 2 and even by 4 in the whole series u get....
  2,3,(x/2),11,23,33.....
  but try to make the seies increasing....
  so (x/2=7)
  hence x=14.... wat say???
• 14 years agoHelpfull: Yes(5) No(18)
• 
  It seems every odd number is 2 more than the one before it. By that rule,
  x = 14
  
• 13 years agoHelpfull: Yes(5) No(2)
• 134-2=132
  132/3=44
  46-2=44
  44-2=42
  42/3=14
  14-2=12
  12/3=4
• 12 years agoHelpfull: Yes(5) No(1)
• here divide every numbers by 2
  2,6,x,22,23,66,67,
  now from above we guess that.. next term will multiple of 2 of following numbers.. 102,103,104,106,107,122,123,124,125,166,167,.....
  so that x=7 which multiple of 2 so ans is 14.
  Now whole series look like 4,12,14,44,46,132,134,204,206,208,212,214,244,246,250,322,324.........
• 13 years agoHelpfull: Yes(2) No(0)
• It seems every odd number is 2 more than the one before it. By that rule, x = 14.
• 13 years agoHelpfull: Yes(1) No(4)
• 14
  4=2*2
  12=2*6
  x=2*7
  44=2*22
  46=2*23
  132=2*66
  134=2*67
  
• 13 years agoHelpfull: Yes(1) No(1)
• 14
  as 44+2=46
  132+2=134
  12+2=14
• 13 years agoHelpfull: Yes(0) No(0)
• 14....as the series proceed we see that
• 12 years agoHelpfull: Yes(0) No(1)
• anw is x=14;
  the diff b/w 44 & 46 is 2
  n 132 &134 is 2
  so the value of x is 2
• 12 years agoHelpfull: Yes(0) No(1)
• x=14 as every odd positioning number(except 1st)in that series.
• 12 years agoHelpfull: Yes(0) No(0)
• It must be 14 because 4*3=12 and 44*3=132 and after 44 we have 46 so after 12 it must be 14.
• 12 years agoHelpfull: Yes(0) No(1)
• 44+2=46 and 132+2=134 so we can say that
  12+2 = 14
• 12 years agoHelpfull: Yes(0) No(0)
• 14.4*3=12 and it is increased by 2.44*3=132. it is increased by 2 so we get 134.
• 12 years agoHelpfull: Yes(0) No(0)
• ans is 14.... as
  4*3=12
  12+2=14
  14*3=42
  42+2=44
  44*3=132
  132+2=134
  
• 12 years agoHelpfull: Yes(0) No(0)