Entry ticket to an exhibition ranges from 1p to 7p. You need to provide exact change at the counter. You have 7p coin. In how many parts will you divide 7p so that you will provide the exact change required and carry as less coins as possible?

• Divide 7p into 3 parts such as 1p,2p,4p.So we can provide Exact change at the counter.i.e 1p for 1p(if the ticket is 1p .
  2p for 2p.//if the ticket is 2p
  1p and 2p for 3p // if the ticket is 3p
  4p for 4p
  1p and 4p for 5p
  2p and 4p for 6p
  1p and 2p and 4p for 7p
• 13 years agoHelpfull: Yes(112) No(3)
• 3 parts: 1, 2, 4
  
  1 = 1
  2 = 2
  3 = 1 + 2
  4 = 4
  5 = 4 + 1
  6 = 4 + 2
  7 = 4 + 2 + 1
  
  :)
• 12 years agoHelpfull: Yes(16) No(2)
• 3 parts
• 13 years agoHelpfull: Yes(13) No(3)
• 3 parts of 1p,2p and 4p.
• 13 years agoHelpfull: Yes(9) No(2)
• Three parts of 1p,2p and 4p.
• 13 years agoHelpfull: Yes(7) No(3)
• Divide 7p coin into 2 parts.
  One as 3p and other as 4p.
  Buy a 4p ticket and carry 3p
• 13 years agoHelpfull: Yes(2) No(18)
• into 3 parts ....1p,2p,4p
  
• 11 years agoHelpfull: Yes(2) No(1)
• the ans will b 3 then one can caryy coin as less as possible .. 1 + 2 +4=7
• 10 years agoHelpfull: Yes(0) No(1)