two identical circle so that their centre,and the point at which they intersect , form a square of side 1cm.Find the area in sq. cm of the portion that is common to the two circles?

• required area= 2*(area of sector) - area of square
  = (pi/2)-1 cm^2
  
• 9 years agoHelpfull: Yes(13) No(0)
• area of one sector is (90/360)*pi*1 cm^2
  area of sq is 1cm^2
  common area = 1-(2*pi/4)=1-pi/2
• 9 years agoHelpfull: Yes(5) No(7)
• (area of 2 quad - area of square)/2
  (pi/4+pi/4-1)/2
  answer will be (pi-2) cm^2
• 9 years agoHelpfull: Yes(2) No(6)
• area of square=1 cm^2
  area of one sector=90/360*3.14*1 cm^2 =0.785 cm^2
  area of remaining portion=area of sq.-area of one sector=.215cm^2
  common area of both the circle= 1-(2*0.215)=0.572cm^2
• 9 years agoHelpfull: Yes(2) No(0)
• sorry! gopikant is 100% correct. coz pi/2 is always greater than 1
• 9 years agoHelpfull: Yes(1) No(1)
• as the angle formed by each portion of the two circle is 90 .so the aarea of that part will be (pi*r^2)/4
  now the area common between two circle is double of this .. i.e. 2*(pi*r^2)/4=(pi*r^2)/2.
  r=1. so the area will be pi/2
• 9 years agoHelpfull: Yes(0) No(2)