A, B, C, D, E, F and G are seven positive integers. And given

a. AB is odd.
b. C+ DE is odd.
c. AD is odd.
d. FACG is odd.
How many of the above integers are odd?

• except E all are odd
• 10 years agoHelpfull: Yes(20) No(1)
• as given AB is odd,so A,&B must be odd no.
  now for AD is odd, so D is also odd.
  now for FACG is odd,F,A,C,G also odd.
  now for C+DE is also odd, and we know C and D is odd. so E must be Even.
  So A,B,C,D,F,G are odd and E is even.
  (N.B:you can easily understand if you think it by taking some numerical value)
• 10 years agoHelpfull: Yes(16) No(2)
• odd*odd=odd; so AB both are odd
  as AD=odd,so D will be odd as well,
  coming to next FACG=odd;so each of them should be odd.
  But in second option its given that C+DE=ODD.....(1) ;(before we got C & D both are Odd)
  so given (1) equation will be odd when E will be even.
  Ans:-Only E is the even integer and rest are ODD.
• 10 years agoHelpfull: Yes(3) No(0)
• Except E all are odd..
• 10 years agoHelpfull: Yes(2) No(2)
• 6 odds will be there
• 10 years agoHelpfull: Yes(2) No(0)
• AB odd => A odd B odd
  C=DE odd => c odd D odd n E Evn
  AD odd => D odd
  FACG odd => F & G odd
  
  ans all are odd except E
  
• 10 years agoHelpfull: Yes(1) No(0)
• ans::6,,,,,,By basics... ODD * ODD=ODD ,,,ODD*EVEN=EVEN,,,EVEN *EVEN=EVEN
• 10 years agoHelpfull: Yes(0) No(0)
• All are odd except E
• 10 years agoHelpfull: Yes(0) No(0)