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If a wire is bent into the shape of a square, then the area of the square is 81sqcm.When wire is bent into a semi-circular shape,then the area of the semi-circle will be?
Read Solution (Total 12)
-
- a^2=81
so a=9
length of wire=4*a=4*9
if semicircle made with that then the circumference will be (pi*r+2*r)=36
hence r=36/(pi+2)
so area of semicircle will be pi*r^2/2=pi*36/(2*(pi+2)^2)=77.0068 - 10 years agoHelpfull: Yes(17) No(3)
Total length of the wire = 4*(route of 81) =36
so perimeter of the semicircle = ( pi*r + 2*r ) = 36;
then; r= 7.
So Area = 1/2 * (pi*r*r) = 77- 10 years agoHelpfull: Yes(14) No(1)
- a^2=81
a=9
now, perimeter of the sqr=4*a=4*9=36= total length of the wire
36=perimeter of the semi circle=pi*r
r=36/pi
area=pi*36*36/pi*pi*2
=206.3 sq unit. - 10 years agoHelpfull: Yes(4) No(14)
- area of square = 81
so side of square = 9
so length of wire = perimeter of square
=9*4
=36
now
perimeter of semi circle = PI*r +2r
= r(pi+2) =36 (since pi+2=5.14)
so r = 7.003
area of semi circle = 1/2 * PI r*2
=154/2
77 - 10 years agoHelpfull: Yes(2) No(1)
- Very sorry for the mistake.
the answer will be 77 sq cm.. - 10 years agoHelpfull: Yes(2) No(0)
KOUSHIKI , Pls do expln.- 10 years agoHelpfull: Yes(1) No(0)
- area of square is given=81sqcm then a^2=81 so a=9
perimeter of square=4*9=36
so total length of the wire==36cm
now length of semi circle=pi*r+2r
so pi*r+2r=36
r=7
area of semicircle=77 - 10 years agoHelpfull: Yes(1) No(0)
- Answer will be 206.36 sq unit..
- 10 years agoHelpfull: Yes(1) No(4)
- area of square is given=81sqcm then a^2=81 so a=9
perimeter of square=4*9=36
so total length of the wire==36cm
now length of semi circle=pi*r+2r
so pi*r+2r=36
r=7
area of semicircle=77
- 10 years agoHelpfull: Yes(1) No(0)
- AREA=pi*R*R/2
R=4.5 - 10 years agoHelpfull: Yes(0) No(6)
- s^2=81
4s=36
2r+pi*r=36
r=7.00
(pi*r^2)/2=76.96 - 10 years agoHelpfull: Yes(0) No(1)
- Here the length of the wire is same.As the wire is bent into a shape of square of area =81cm2and side2=area of squareso side =81−−√=9×9−−−−√=9cmHence side of the square =9cmand it has four sides, so length of the wire used is 9×4=36cmAnd circumference of a circle =2πrso circumference of semi−circle=2πr/2=πrthis circumference of semi−circle=length of the wireHence πr =36cm⇒r=36/πAs Area of semicircle =πr2/2 Area of semicircle=π(36)22π2=(36*36)/2pi = 206.3(ans)
- 10 years agoHelpfull: Yes(0) No(4)
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