In how many ways a team of 11 must be selected from 5 men and 11 women such that the

(11c11)+(5c1*11c10)+(5c2*11c9)+(5c3*11c8)=2256 ways
9 years agoHelpfull: Yes(11) No(1)
5C1*11C8+5C2*11C9+5C1*11C10+5C0*11C11
=2256
9 years agoHelpfull: Yes(6) No(1)
let w and m denotes the probability of selecting women and men.
if only women are selected then P(w)=11C11/16C11
if 1 man and 10 women are selected then P(w)*P(m)=(5C1*11C10)/16C11
if 2 men and 9 women are selected then P(w)*P(m)=(5C2*11C9)/16C11
if 3 men and 8 women are selected then p(w)*P(m)=(5C3*11C8))/16C11
total probability=(11C11 + 11C10*5C1 + 11C9*5C2 + 11C8*5C3)/16C11
=47/91.
9 years agoHelpfull: Yes(5) No(0)
47/91
(11C11 + 11C10*5C1 + 11C9*5C2 + 11C8*5C3)/16C11
9 years agoHelpfull: Yes(3) No(0)
5c3*11c8 + 5c2*11c9 + 5c1*11c10
9 years agoHelpfull: Yes(1) No(1)
11C11 + 11C10*5C1+11C9*5C2 + 11C8*5C3
9 years agoHelpfull: Yes(1) No(1)
(11c11)+(5c1*11c10)+(5c2*11c9)+(5c3*11c8)
1+55+825+150
1030 ans
9 years agoHelpfull: Yes(0) No(4)
(11c11)+(5c1*11c10)+(5c2+11c9)+(5c3+11c8)
9 years agoHelpfull: Yes(0) No(0)
(11c11)+(5c1*11c10)+(5c2+11c9)+(5c3+11c8)
9 years agoHelpfull: Yes(0) No(1)

In how many ways a team of 11 must be selected from 5 men and 11 women such that the team must comprise of not more than 3 men?