Batting Average for 40 innings of a cricketer is 50 runs. His highest score exceeds his lowest score by 172 runs .if the two innings are excluded , the average of the remaining 38 innings is 48 runs. Highest score of the playeris

• ans) 174
  total run=40*50=2000
  total run in 38 inn=38*48=1824
  total ru in remaining two inn=(2000-1824)=176
  highest-lowest=172
  highest+lowest=176
  highest=174
• 10 years agoHelpfull: Yes(6) No(2)
• let lowest score be x,then highest score =x+172
  after excluding lowest and highest score average of 38 innings=48
  i.e 2runs from each inning got decremented =2*38
  so
  x+(x+172)=2*50+ (extra runs deducted i.e 2*38)
  => 2x+172=100+176=176
  => 2x=4 => x=2
  therefore highest score =x+172=174
• 9 years agoHelpfull: Yes(2) No(0)
• 2000-1824=176
  So , 176-4=176
  Highest=176
  Lowest=4
• 10 years agoHelpfull: Yes(1) No(3)
• Avg of 40 innings=50-->no. of runs=40*50=2000
  Avg of 38 innings=48-->no. of runs=38*48=1824
  Let x be lowest score.x+172 is highest score.
  x+x+172=2000-1824(becoz two innings scores have to be removed)
  2x+172=176
  x=2
  Highest score=2+172=174
• 8 years agoHelpfull: Yes(1) No(0)
• total runs=40*50=2000
  H-L=172
  total runs excluding H and L are=38*48=1824
  total remaining runs=2000-1824=176
  As H-L=172(176-174=2)
  H-2=172=>H=172+2=174
  Ans:174
• 7 years agoHelpfull: Yes(1) No(0)
• ans is 174
• 9 years agoHelpfull: Yes(0) No(1)
• the highest score of the player is 174.
• 9 years agoHelpfull: Yes(0) No(0)
• avg for 40 innings is 50 -> total runs =50*40=2000 runs.
  same way, 48*38=1824. subtracting both we get highest and lowest scores sum.
  2000-1824=176, 174-2=172 which is the diff b/w highest and lowest scores.
  therefore highest score=174
• 9 years agoHelpfull: Yes(0) No(0)