TCS
Company
Numerical Ability
Permutation and Combination
In how many ways 7 different objects be divided among 3 people so that either one or two of them do not get any object?
1)36
2)180
3)84
4)381
Read Solution (Total 7)
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- case 1: one person gets nothing
Ways of choosing one person=3c1
ways of distributing 7 items between 2 people is 2^7
but it also contains a case where B and C doesnt gets anything
therefore no. of ways=2^7-2
case 2:
Two person doesnt get anything
hence no of ways=3
Therefore total ways=3c1(2^7-2)+3=378+3=381
Answer is 381 - 9 years agoHelpfull: Yes(26) No(6)
- 36.
(7+3-1)c(3-1)=9c2=(9*8)/2=36. - 9 years agoHelpfull: Yes(2) No(5)
- n+r-1Cr-1
9C3=84
so ans is 84 - 9 years agoHelpfull: Yes(1) No(7)
- 126*3+3=281
- 9 years agoHelpfull: Yes(1) No(0)
- what the correct ans plz
- 9 years agoHelpfull: Yes(1) No(0)
- Ans will be 36
- 9 years agoHelpfull: Yes(0) No(1)
- 381 ans....
- 9 years agoHelpfull: Yes(0) No(1)
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