Three distinct single digit numbers A, B & C are in G.P. If abs(x) for real x is the absolute value of x, then the number of different possible values of abs(A+B-C) is
1)5
2)6
3)4
4)3

• the answer could be 5 different possible values
  1,2,4 and 4,2,1
  2,4,8 and 8,4,2
  1,3,9 and 9,3,1
  abs(x) could be 1,5,2,10,11
• 10 years agoHelpfull: Yes(19) No(1)
• There can be 6 possible GP sequences:
  1 ,2 ,4 and 4, 2, 1
  2, 4, 8 and 8, 4, 2
  1, 3, 9 and 9, 3, 1
  Corresponding values for abs(a+b-c) are 1, 5, 2, 10, 5, 11
  so ans=6
  
• 10 years agoHelpfull: Yes(2) No(4)
• Possible GP series between 1 to 9 are
  1,2 4 4,2,1 difference = 2
  2,4,8 8 ,4,2 difference = 2
  so 4 values possible of (A+B-C)
• 10 years agoHelpfull: Yes(1) No(2)
• There can be 6 possible GP sequences:
  1 ,2 ,4 and 4, 2, 1
  2, 4, 8 and 8, 4, 2
  1, 3, 9 and 9, 3, 1
  Corresponding values for abs(a+b-c) are 1, 5, 2, 10, 5, 11
  so ans=4
  
• 10 years agoHelpfull: Yes(1) No(3)
• abs(1+2-4)=1
  abs(4+2-1)=5
  abs(3+1-9)=5
  abs(9+3-1)=11
  abs(8+4-2)=10
  abs(2+4-8)=2...like wise we get the values
  
• 10 years agoHelpfull: Yes(1) No(0)
• Answer will be 4
• 10 years agoHelpfull: Yes(0) No(3)
• There can be 4 possible GP sequences:
  1 ,2 ,4 and 4, 2, 1
  2, 4, 8 and 8, 4, 2
  Corresponding values for abs(a+b-c) are 1, 7, 2, 10
  so ans=4
• 10 years agoHelpfull: Yes(0) No(3)
• @MEGHA values will be 1,5,2,10 respectively not 1,7,2,10
• 10 years agoHelpfull: Yes(0) No(1)
• 
  Suman it should be 5 as per ur logic
  
• 10 years agoHelpfull: Yes(0) No(0)
• 6 possible combinations .
  gp
  1 2 4 =1 & 4 2 1=5
  2 4 8=2 & 8 4 2=10
  1 3 9=5 & 9 3 1=11
• 10 years agoHelpfull: Yes(0) No(0)
• how these values came as a possible values??( as every1 has answered 1,5,2 ,10,11)
  plz explain !!
• 10 years agoHelpfull: Yes(0) No(0)
• i didnt get it
• 10 years agoHelpfull: Yes(0) No(0)