If 28a+30b+31c=365.(I was unable to solve this question during my online test on 6th sept 12)
then a+b+c=?.a,b,c are natural numbers

• have a look on your calender
  since,we all knw a year consist of 365 days
  february is d only month which has 28 days
  4 months in a year has 30 days
  and,rest 7 months has 31 days..
  so,following d given eq. we can write 28*1 + 30*4 + 31*7..
  hence values of a,b and c are 1, 4 and 7 respectively..
• 9 years agoHelpfull: Yes(40) No(0)
• 12 is the ans
• 9 years agoHelpfull: Yes(0) No(1)
• a=1 the month having 28 days for leap year
  b=4 the months having 30 days
  c=7 the months having 31 days
  
• 9 years agoHelpfull: Yes(0) No(0)
• based on calender having 365 days
  no. of months having 28 days=1
  no. of months having 30 days=4
  no. of months having 31 days=7
  total=7+4+1=12
• 9 years agoHelpfull: Yes(0) No(0)
• ans is=12.
  as a=1 (only feb. have 28 days)
  b=4(i.e.4 months have 30 days)
  c=7(7 months have 31 days)
  so a+b+c=1+4+7=12
  
• 9 years agoHelpfull: Yes(0) No(0)
• The calender concept is most common approach and yields 1,4,7.
  However if you do not find 1,4,7 in the options... 2,1,9 is the other possible solution.
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• just the calender of the year so a+b+c=12
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• 12
  one year contains 365 days so x+y+z will be sum of months
  
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• take the values given in options and substitute in given equation answer wil be equal to 365 when the option satisfies in values of a ,b ,c
• 5 years agoHelpfull: Yes(0) No(0)