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7 find the no. of polynomial for degree of x>+1 where f(x2)=f(x)2=f(f(x))

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If 28a+30b+31c=365.(I was unable to solve this question during my online test on 6th sept 12)
then a+b+c=?.a,b,c are natural numbers find the no. of polynomial for degree of x>+1 where f(x2)=f(x)2=f(f(x))