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10 one question was x*y^2*z<0 then
a)x<0
b)xyz<0
c)xz<0
d)None of the
Read Solution (Total 7)
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- if we take y^2 then it will always greater than zero so only one option z left i.e. xz
- 10 years agoHelpfull: Yes(6) No(0)
- c is correct.
- 10 years agoHelpfull: Yes(0) No(3)
- c is correct.
- 10 years agoHelpfull: Yes(0) No(1)
- here y^2 should not be
- 10 years agoHelpfull: Yes(0) No(0)
- correct ans is c
- 10 years agoHelpfull: Yes(0) No(0)
- y^2 gives always +ve number..if xz
- 10 years agoHelpfull: Yes(0) No(0)
- xz
- 10 years agoHelpfull: Yes(0) No(0)
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