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Numerical Ability
Permutation and Combination
A team of 11 member is to be formed from a group of 5 men and 8 women. At most 3 men are allowed. How many combination are possible.
Read Solution (Total 9)
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- At most 3 men means not more than 3,
Case 1 All women not possible
Case 2 10 women and 1men not possible
Case 3 9 women and 2 men not possible
Case 4 8 women and 3 men =5C3 * 8C8 = 10. - 10 years agoHelpfull: Yes(21) No(6)
- 11c11+5c1*11c10+5c2*11c9+5c3*11c8
- 10 years agoHelpfull: Yes(7) No(13)
- As total women are 8 and maximum of 3 men can be selected out of 5.if we select 2 men then team will not form coz 2men + 8 women =10 member but 11 required. So, the only choice is
8C8 * 5C3=10 - 10 years agoHelpfull: Yes(3) No(0)
- 10 is the ans
- 10 years agoHelpfull: Yes(0) No(1)
- total combinations=5c3 * 8c8
= 10 *1=10 - 10 years agoHelpfull: Yes(0) No(0)
- 5C3*8C8=10
- 10 years agoHelpfull: Yes(0) No(0)
- no. of women=8
no. of men=5
team is of 11 member
so now only find combination for selecting men i.e.-
5c3=10 ans.. - 10 years agoHelpfull: Yes(0) No(0)
- 8c8+5c3
0nly one combination is possible
- 10 years agoHelpfull: Yes(0) No(2)
- anser is 5c3*8c3=10
- 10 years agoHelpfull: Yes(0) No(0)
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