in how many ways u can form a group of 11 members from 5 men and 11 women if the

11c11+(11c10*5c1)+(11c9*5c2)+(11c8*5c3)
10 years agoHelpfull: Yes(14) No(1)
we need team members=11 such that there should not be more than 3 men
so the conditions are (3M,8W),(2M,9W),(1M,10W)
Now, no. of ways=11c11+5c3*11c8+5c2*11c9+5c1*11c10=2256
10 years agoHelpfull: Yes(3) No(0)
11 members from 5 men and 11 womes
1) step----- 11c11(here 0 man)
2) step 5c1*11c10(means 1 man out of 5 and 10 women out of 11)
3) step ---------5c2* 11c9(means 2 man out of 5 and 9 women out of 11)
4) step 5c3*11c8(means 3 man out of 5 and 8 women out of 11)
in above question not more than 3 man so ans
will 11c11+(11c10*5c1)+(11c9*5c2)+(11c8*5c3)=2256
10 years agoHelpfull: Yes(3) No(0)
11c11+(11c10*5c1)+(11c9*5c2)+(11c8*5c3)=2256
9 years agoHelpfull: Yes(1) No(0)
8x=5(26-x)
x=10
10 years agoHelpfull: Yes(0) No(10)
5co*11c11 + 5c1*11c10 + 5c2*11c9 + 5c3*11c8 =2256
10 years agoHelpfull: Yes(0) No(0)
in this question its not given at most 3 men..
so, we cant take 11c11 bcz 3 men r there in the group.
therefore
(5c3)*11c8=150
9 years agoHelpfull: Yes(0) No(1)

in how many ways u can form a group of 11 members from 5 men and 11 women if the men member not more than 3?