In a cart the ratio of the area of the front wheel to back wheel is 125:180.distance travelled by front wheel is six times that of back wheel.if circumference of back wheel is 36 ft,find distance travelled by the cart?

• ans: 1080ft.
  
  ratio of front wheel to back wheel= 125:180=25:36
  
  suppose area of front wheel=25x
  and of back wheel=36x
  
  let radius of front wheel= r
  and of back wheel=R
  pie*R^2=36x
  =>R=sqrt(36*x/pie)
  cicumference of back wheel=36ft.
  2*pie*R=36
  =>2*pie*sqrt(36*x/pie)=36
  after solving this, x=63/22
  then area of front wheel=25x
  =>pie*r^2=25*63/22
  after solving this, r=105/22
  circumference of front wheel=2*pie*r
  2*3.14*105/22=30
  so, dist. traveled by cart=36*30=1080ft.
• 10 years agoHelpfull: Yes(10) No(5)
• pls solve ths as soon as possible.......these questions have no father nd mother......very f**cing questions
• 10 years agoHelpfull: Yes(6) No(3)
• how it can be possible two wheels of cart travel different distance?
• 10 years agoHelpfull: Yes(5) No(2)
• Options were 900 ft, 1080 ft, n rest approx 261 ft,496 ft
• 10 years agoHelpfull: Yes(2) No(2)
• r1^2:r2^2= 5x5x5:5x36 thus r1:r2= 5:6
  (2*pi*r1)/(2*pi*r2) = x/2*pi*36
  r1/r2 = x/2*pi*36 =5/6 thus x=60pi
  
  
  
• 10 years agoHelpfull: Yes(1) No(8)
• r1^2/r2^2 = 125/180 => r1/r2= 5/36
  and 2* Pie * r1 =6*36 ft => r1= 108/pie
  distance travelled by cart = 2*108/pie *pie => 216
• 10 years agoHelpfull: Yes(1) No(1)
• is it 900??
  
• 10 years agoHelpfull: Yes(0) No(8)