In a year N, the 259th day of the year is a Saturday. In the year N+l, the 222th day of the year is also a Saturday. What is the 119th day of the year N-l?
a) Thursday
b) Saturday
c) Friday
d) Tuesday

• as 259th day of year N and 222th day of year N+1 is same i.e saturday, so number of day between above 2 day is must be divided by 7..
  no. of days btwn dis 2 day may b (366-259)+222=329----(1) or (365-259)+222=328------(2)
  as 329 is divided by 7 so year N is leap year son Year N-1 is not a leap year....
  now number of day btwn 119th of N-1 and 259th of N is (365-119)+259 =505
  now 505/7 gives remainder 1 , so 504 is divided by 7, so 120th day of N-1 is saturday...so 119th day of N-1 is Friday
• 9 years agoHelpfull: Yes(17) No(0)
• N yr 259th Saturdayy = 365-259=106 remaining days
  N+1 222nd Saturday 106+222=328 dayss
  to determine day which of week =
  328%7=6
  ie 6 = fridayy
  c is correct
• 10 years agoHelpfull: Yes(11) No(7)
• c) Friday
  Year n-1 starts on saturday and ends on sunday. So 119th day is a friday
• 10 years agoHelpfull: Yes(8) No(9)
• ans is friday ...year n+1 is leap year...because 259-222= 37
  it means from year n to n-1 thr is diff of 2 days ...if it is ordnry year thn diff will be 1 day bt its leap year thrfr diff is 2 days..
  
  259 is satrday 259-119 = 140 it will be friday...........
• 10 years agoHelpfull: Yes(5) No(1)
• If we consider leap year then it may be Friday also. and if not then it is thursday
• 10 years agoHelpfull: Yes(3) No(4)
• n-1 means it is friday because n is given here saturday
  
• 10 years agoHelpfull: Yes(1) No(1)
• Take the Nth year. In the Nth year 259th is a Saturday.
  In the N+1 the year, 222 nd day is also Saturday.
  So there must be 0 odd days between these days.
  And we don’t have any information, whether Nth year is leap or not.
  Case 1 : Let us assume Nth is an ordinary year
  Then number of days between these 2 days => (366 - 259) +222 = 328 days
  In 328 days, we have 1 odd day . So we can say that N th year is not an ordinary year.
  Case 1 : Let us take Nth year is leap,
  Number of days between these 2 days => (366 - 259 ) = 329 days
  In 329 days ,we have 0 odd day . So we can say that N th year is leap year
  As Nth year is leap , N-1 th year is not a leap year.
  Number of days between 259 th day of Nth year and 119 th day of N-1 th year
  = 259 + (365-119)
  = 505 days
  The number of odd days in 505 days =>1 odd day
  Therefore , 119th day of the year N-1 => Saturday -1 = Friday
• 9 years agoHelpfull: Yes(1) No(1)