1!+2!+3!+4!+...+50!

• 1!+2!+3!+4!+...+50!
  = 50! (1!/50! + 2!/50! + .........49!/50! + 50!/50! )
  = 50! (1!/50! + 2!/50! + .........1/50 + 1 )
  in the bracket only 1/50 and 1 have values other will be negligible,
  so approximately we can write
  = 50! (51/50 )
  = 1.02*50
  = 1.02 * 3.04 * 10^64
  = 3.1008 * 10^64
• 9 years agoHelpfull: Yes(1) No(2)
• Data Inadequate..but actual question is..
  1!+2!+3!+4!+5!.....50!/5!
  then 1!+2!+3!+4!/5!
  1+2+6+24/5!
  33/5!
  33/120
  33 Remainder...Ans..!!!
• 9 years agoHelpfull: Yes(0) No(1)