Exam
Maths Puzzle
Numerical Ability
1!+2!+3!+4!+...+50!
Read Solution (Total 2)
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- 1!+2!+3!+4!+...+50!
= 50! (1!/50! + 2!/50! + .........49!/50! + 50!/50! )
= 50! (1!/50! + 2!/50! + .........1/50 + 1 )
in the bracket only 1/50 and 1 have values other will be negligible,
so approximately we can write
= 50! (51/50 )
= 1.02*50
= 1.02 * 3.04 * 10^64
= 3.1008 * 10^64 - 10 years agoHelpfull: Yes(1) No(2)
- Data Inadequate..but actual question is..
1!+2!+3!+4!+5!.....50!/5!
then 1!+2!+3!+4!/5!
1+2+6+24/5!
33/5!
33/120
33 Remainder...Ans..!!! - 10 years agoHelpfull: Yes(0) No(1)
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