#include
void main()
{
int a,b;
scanf("%d%d",&a&b);
printf("%d*%d%d",a,b);
}

output?

• depends on input:ex: 5,3
  o/p will be 5*33
• 10 years agoHelpfull: Yes(4) No(1)
• There is one error in scanf("%d%d",&a&b); There should be a space between &a and &b. However avoiding the error if we are to find the solution then it will depend on the input provide. For example I provide 5 and 6 as input, then the result displayed will be
  5*30 where 0 will be automatically included.
• 10 years agoHelpfull: Yes(3) No(2)
• Depends on the input
  if input is 12, 3
  then
  op- 12*3(Garbage)
• 10 years agoHelpfull: Yes(2) No(2)
• lots of error...
  
  scanf is not necessary
  
  If the printf has a valid arguments for a and b, then it will print the right value of a followed by * then followed by garbage values of b
• 10 years agoHelpfull: Yes(1) No(0)
• if a=3,b=5
  3*5garbage
• 9 years agoHelpfull: Yes(1) No(0)
• multiplation of two number is print not garbage
  
• 10 years agoHelpfull: Yes(0) No(1)
• it will show error because in scanf() there will be comma(,)btween &a and &b
• 10 years agoHelpfull: Yes(0) No(1)
• error
  it will give syntax error on compiling it
• 10 years agoHelpfull: Yes(0) No(0)
• This gives error in printf, too few arguments for format
• 10 years agoHelpfull: Yes(0) No(0)
• First of all there is an error in the scanf() statement.There must be a comma ( , ) between &a and &b.
  Avoiding this error the output will be the value of a,* and two times the value of b.
  For example,
  If you give 4 & 5 as the value of a & b respectively then the O/P is 4*55
• 10 years agoHelpfull: Yes(0) No(0)
• depend on inputs
  for ex a=2,b=3
  out put is 2*3
• 10 years agoHelpfull: Yes(0) No(1)
• if u enter 2 and 5 then output=2*5 and some garbage value
  i.e 2*5garbage=2*52131232123
• 9 years agoHelpfull: Yes(0) No(0)
• it gives an error.because there is no space between &a and &b
• 9 years agoHelpfull: Yes(0) No(0)
• output depends on inputs for ex- a=3 and b=10 then output is :
  3*3with random number due to extra %d
• 9 years agoHelpfull: Yes(0) No(0)