C Programming and Technical Programming Program

#include
void main()
{
int a=100;
printf("%d",a);
printf("%5d",a);
printf("%-5d",a);
}

output???????

Read Solution (Total 9)

100 100100
For first printf statement it is simply printing the value of a i.e. 100. In second printf statement %5d refers to 5 white spaces to be printed before the integer value. So there are 5 white spaces. In the last printf statement %-5d refers to printing the value from the very left side.
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100 100100
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output:
100
100(after five space 100 will be printed in the case of "%5d")
100
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100100100
it prints a each time
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100 100100
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100 100100 _
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100
100
100
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100
100
100
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output will be 100 100100
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C Other Question

#include
void main()
{
int a,b;
scanf("%d%d",&a&b);
printf("%d*%d%d",a,b);
}

output? #include
void main()
{
int a,b;
scanf("%d*%d%d,&a,&b);
printf("%d%d",&a,&b);
}

output???