How many pairs of natural numbers are there as the difference of whose squires is 45?

• a^2 -b^2 = 45
  
  (a+b)(a-b) = 45
  
  45 = 45*1 or 9*5 or 15*3
  
  if a+b =45
  and a-b = 1
  a = 23 and b = 22
  
  if a+b = 9
  and a-b = 5
  a = 7 and b = 2
  
  if a+b =15 and
  a-b = 3
  a= 9 and b = 6
  
  So there are clearly 3 pairs of natural numbers which satisfy this
• 9 years agoHelpfull: Yes(0) No(0)