if n is positive integer and (n+1)(n+3) is odd,then (n+2)(n+4) must be a multiple of which one of the following? A) 3 B) 6 C) 8 D) 16

• c.) 8
  simply put the value and take division
• 10 years agoHelpfull: Yes(1) No(0)
• Given n is a positive integer so submit n=1,2,3,4,5,6,7,8.....
  and it is also given that (n+1)(n+3) is odd this statement is true only for values of n=2,,4,6,8 i.e, even numbers.
  submit n=2,4,6,8 in (n+2)(n+4)
  for n=2 (n+2)(n+4)=24
  for n=4 (n+2)(n+4)=48
  for n=6 (n+2)(n+4)=80
  for n=8 (n+2)(n+4)=120
  from above we can say that all 24,48,80,120 are all divisible by 8 hence answer is 8
• 7 years agoHelpfull: Yes(1) No(0)
• solve through option
  Ans is option : c)
  
• 10 years agoHelpfull: Yes(0) No(0)