george does 3/5th of a piece of work in 9 days. he than calls in poul and they finish the work in four days. How long will paul take to do the work by himself?

• 3/5 work in 9 day - george
  whole work in (9*5)/3 = 15 day
  remaining work = 1-3/5 =2/5
  
  both of them done 2/5 of work in 4 day
  both together complete whole work in = (4*5)/2 = 10 day
  
  1/george +1/paul =1/10
  1/15 +1/paul = 1/10
  1/paul = 1/10 - 1/15
  = (3-2)/30 = 1/30
  hence paul complete whole work in 30 days.
• 9 years agoHelpfull: Yes(19) No(1)
• george takes 15 days to complete the wrk
  they have to do 2/5 wrk
  in 4 days
  thus
  4/15 + 4/x = 2/5 where x is of paul. x=30
• 9 years agoHelpfull: Yes(12) No(3)
• george completes the whole work in 15 days in one day 1/15
  and both of them complete remainin 2/5 work in 4 days it means in one day they finish 1/10 work
  so 1/george+1/paul=1/10;
  paul=30 days
• 9 years agoHelpfull: Yes(3) No(2)
• 3/5 work for george in 9 days , so in 1 one he will do (3/5)/9=1/15, so in 4 days he will do 4/15, assume poul does x in one days so 4x in 4 days. So 4x+1/15=1-3/5
  x=1/30.
  So answer is 30.
• 8 years agoHelpfull: Yes(0) No(0)