George walks 36 kms partly at a speed of 4 kms per hour and partly at 3 km per hour If he had walked at a speed of 3km per hour when he had walked at 4 and 4 km per when he had walked at 3 he would have walked only 34 kms. The time (in hours) spent by George in walking was)

• the question can be solved with the help of two equations...
  4x+3y=36----equ(1)
  3x+4y=34----equ(2)
  by solving these two equations
  x=6 and y=4
  so total time is 10hours.
• 10 years agoHelpfull: Yes(25) No(4)
• x/4=t1 36-x/3=t2;
  3*x/4 + 4*(36-x)/3=34
  solving 2nd equation
  we get x=24
  piutting in above we get t1=6 and t2=4 so time os 6+4= 10 hrs
• 10 years agoHelpfull: Yes(9) No(0)
• let T be the time of the complete journey.
  let t be the time when he walked at 4kmph.
  so (T-t) is the time when he walked at 3kmph.
  A/q
  4t+3(T-t)=36
  3t+4(T-t)=34
  on solving
  we get T=10 Hours
  
• 10 years agoHelpfull: Yes(1) No(0)
• TOTAL JOURNEY TIME IS 11 HOURS.
  
• 10 years agoHelpfull: Yes(0) No(10)
• 4x+3y=36.............eqn1
  3x+4y=34.............eqn2
  
  solving it gives 10 hours
• 4 years agoHelpfull: Yes(0) No(0)
• here we have 2 cases:
  case 1 d1=36km and let us assume time reqd to walk at 3kmph t3=x and t4=y
  so applying d=speed x time
  36=3x+4y
  case 1 d1=34km and let us assume time reqd to walk at 4kmph t4=x and t3=y
  so applying d=speed x time
  34=4x+3y
  
  equating the two equations we get x=4hrs & y=6 hrs so total time taken=6+4=10hrs
• 3 Months agoHelpfull: Yes(0) No(0)