A and B completed a work together in 5 days. Had A worked at twice the speed and B at half the speed, it would have taken them four days to complete the job. How much time would it take for A alone to do the work

• A takes 10 days to complete work alone.
  (1/x)+(1/y)=1/5..................(1)
  (2/X)+(1/2Y)=1/4...............(2)
  solve equ 1 and 2
  5x+5y=8y+2x
  x=y.
  x=10
  y=10
  
• 9 years agoHelpfull: Yes(15) No(0)
• A takes 10 days
  (1/x)+(1/y)=1/5
  (2/x)+(1/2y)=1/4
  solving these 2 eq. gives
  A=10 days and B=10 days
  
• 9 years agoHelpfull: Yes(1) No(0)
• i think this is dummy question
  because A completes it in 5 days acc to second case but acc to 1st case they both complete together in 5 days
  its contradiction
  thus may b dummy one
  
• 9 years agoHelpfull: Yes(0) No(3)
• plz give sol of this
  
• 9 years agoHelpfull: Yes(0) No(0)
• given thet
  1/A + 1/B = 1/5
  => 1/B=1/5-1/A
  
  if a works twice the speed... work done in 1 day= 2/A, and at half speed ... B works = 1/2B
  
  so,
  2/A+1/2B =1/4
  solving we get
  a= 10 days
  
• 9 years agoHelpfull: Yes(0) No(0)