There are ten bags. and 1000 coins. These 1000 coins should be arranged in into these (10) bags in any denomination, in such a way that when you are asked to give a certain no: of coins, u should be able to give by picking few bags and tell , here it is, say for eg: if asked 433 u should be able to give 433 by picking 5 or 6 bags, like that if asked 1 coin also u should be able to give in similar manner. How it can be arranged?

• You set the no. of coins as powers of 2 except for the last bag where you just place whatever remains.
  Bag 1 = 1 coin
  Bag 2 = 2 coins
  Bag 3 = 4 coins
  Bag 4 = 8 coins
  Bag 5= 16coins
  Bag 6= 32coins
  Bag 7=64 coins
  Bag 8= 128 coins
  Bag 9= 256 coins
  Bag 10= 488 coins ( If the total no = 1024 coins this should be 512)
• 10 years agoHelpfull: Yes(1) No(0)
• Bag1 - 1 Coin , Bag2- 2 Coins ,Bag3- 4 Coins, Bag4 - 8 Coins ,Bag5 - 16 coins . Bag6- 32 coins ,bag7 -64 Coins , bag8 128 coins , bag9 - 256 coins , bag10- 489 i.e each bag should have one coin extra from the total of all the coins available in the each bag before it. and the 10 bag varies and the remaining of the coins after completion of bag 9 goes in to 10th..
• 10 years agoHelpfull: Yes(0) No(0)