In the general elections, the parties 1, 2 and 3 got votes as 45, 12 and 43% respectively. If a total of 16000 people voted, then by what number of votes did the coalition of party 2 and 3 win?

• ATP:PARTY 2 & 3 GOT 12 AND 43% RESPECTIVELY=55% AS A WHOLE.
  SO 55% OF 16000=8800.
  AND PARTY 1 GOT 45% VOTE=45%OF 16000=7200.
  MARGIN OF VOTES = 8800-7200=1600 IS THE ANSWER
• 9 years agoHelpfull: Yes(27) No(0)
• its (43%+12%) of 16000=8,800
  45% of 16000=7200
  so 1 n 2 won by 1600 votes
  
• 9 years agoHelpfull: Yes(4) No(1)
• combined % of 2 and 3 is 55%. Hence, 55% OF 16000
• 9 years agoHelpfull: Yes(0) No(0)
• 8,800 votes ( ((12+43)/100)*16000 )
  Coalition = temporary alliance
• 9 years agoHelpfull: Yes(0) No(0)
• 8800
  because 45%of 16000 is 7200 thus sub from total we get the ans
  
• 9 years agoHelpfull: Yes(0) No(1)
• PARTY 2 & 3 GOT 12 AND 43% RESPECTIVELY=55% AS A WHOLE.
  SO 55% OF 16000=8800.
  AND PARTY 1 GOT 45% VOTE=45%OF 16000=7200.
  MARGIN OF VOTES = 8800-7200=1600
• 9 years agoHelpfull: Yes(0) No(0)
• 43%+12%=55%,
  by 10% the coalition party wins
  so 10% of 16000=1600 is ans
• 9 years agoHelpfull: Yes(0) No(0)
• Firstly 1% of 16000 votes= 160
  so,
  party 1 =45*160=7200
  hence
  Parties 2&3 got= 55*1600=8800
  margin of votes=8800-7200=1600 will final answer
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• 2 & 3 parties=(12%+43%) of 16000=8800
  1 party=45% of 16000=7200
  won by a difference of 1600 (8800-7200)
• 9 years agoHelpfull: Yes(0) No(0)
• total no.of votes=16000
  100%->16000
  1 st person got 45%->7200
  2nd person got 43%->6880
  diff b/w them is 320 votes
  3 rd person got 12%->1920
  1920-320=1600 votes
• 5 years agoHelpfull: Yes(0) No(0)
• one got 45%,second got 12% and third got 43% ,
  now the 1% of 16000 is = 160.
  So,160 x 12(which is got by the 2 party)=1920,
  and 3 is got by the 160 x 43=6880,
  and1 party got 160 x 45 = 7200;
  now add the 2 & 3 party votes= 8800,
  and subtract by 3 party vote : 8800-7200=1600,
• 4 years agoHelpfull: Yes(0) No(0)